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JEE Main 2023 (Online) 10th April Evening Shift

MCQ+4 / -12023

Let \(\mu\) be the mean and \(\sigma\) be the standard deviation of the distribution



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\({x_i}\) 0 1 2 3 4 5
\({f_i}\) \(k + 2\) \(2k\) \({k^2} - 1\) \({k^2} - 1\) \({k^2} + 1\) \(k - 3\)


where \(\sum f_{i}=62\). If \([x]\) denotes the greatest integer \(\leq x\), then \(\left[\mu^{2}+\sigma^{2}\right]\) is equal to :

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