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JEE Main 2023 (Online) 31st January Morning Shift

INTEGER+4 / -12023

The enthalpy change for the conversion of \(\frac{1}{2} \mathrm{Cl}_{2}(\mathrm{~g})\) to \(\mathrm{Cl}^{-}\)(aq) is (\(-\)) ___________
\(\mathrm{kJ} \mathrm{mol}^{-1}\) (Nearest integer)


Given : \(\Delta_{\mathrm{dis}} \mathrm{H}_{\mathrm{Cl}_{2(\mathrm{~g})}^{\theta}}^{\ominus}=240 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta_{\mathrm{eg}} \mathrm{H}_{\mathrm{Cl_{(g)}}}^{\ominus}=-350 \mathrm{~kJ} \mathrm{~mol}^{-1}\),


\({\mathrm{\Delta _{hyd}}H_{Cl_{(g)}^ - }^\Theta = - 380}\) \(\mathrm{kJ~mol^{-1}}\)

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