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Alternating Current

JEE Main 2022 (Online) 26th July Morning Shift

MCQ+4 / -12022

In a series \(L R\) circuit \(X_{L}=R\) and power factor of the circuit is \(P_{1}\). When capacitor with capacitance \(C\) such that \(X_{L}=X_{C}\) is put in series, the power factor becomes \(P_{2}\). The ratio \(\frac{P_{1}}{P_{2}}\) is:

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