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Limits Continuity And Differentiability

JEE Main 2022 (Online) 28th June Evening Shift

MCQ+4 / -12022

The value of

\(\mathop {\lim }\limits_{n \to \infty } 6\tan \left\{ {\sum\limits_{r = 1}^n {{{\tan }^{ - 1}}\left( {{1 \over {{r^2} + 3r + 3}}} \right)} } \right\}\) is equal to :

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