The equilibrium constant for the reversible reaction 2A(g) \rightleftharpoons 2B(g) + C(g) is K 1 {3 \over 2}A(g) \rightleftharpoons {3 \over 2}B(g) + {3 \over 4}C(g) is K 2 . K 1 and K 2 are related as :

Jee Main

Chemical Equilibrium

JEE Main 2022 (Online) 30th June Morning Shift

MCQ+4 / -12022

The equilibrium constant for the reversible reaction

2A(g) \(\rightleftharpoons\) 2B(g) + C(g) is K₁

\({3 \over 2}\)A(g) \(\rightleftharpoons\) \({3 \over 2}\)B(g) + \({3 \over 4}\)C(g) is K₂.

K₁ and K₂ are related as :