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JEE Main 2021 (Online) 22th July Evening Shift
MCQ+4 / -12021
The motion of a mass on a spring, with spring constant K is as shown in figure.

The equation of motion is given by
x(t) = A sin\(\omega\)t + B cos\(\omega\)t with \(\omega\) = \(\sqrt {{K \over m}}\)
Suppose that at time t = 0, the position of mass is x(0) and velocity v(0), then its displacement can also be represented as x(t) = C cos(\(\omega\)t \(-\) \(\phi\)), where C and \(\phi\) are :

The equation of motion is given by
x(t) = A sin\(\omega\)t + B cos\(\omega\)t with \(\omega\) = \(\sqrt {{K \over m}}\)
Suppose that at time t = 0, the position of mass is x(0) and velocity v(0), then its displacement can also be represented as x(t) = C cos(\(\omega\)t \(-\) \(\phi\)), where C and \(\phi\) are :
