Jee Main
Electrostatics
JEE Main 2021 (Online) 1st September Evening Shift
MCQ+4 / -12021
A cube is placed inside an electric field, \(\overrightarrow E = 150{y^2}\widehat j\). The side of the cube is 0.5 m and is placed in the field as shown in the given figure. The charge inside the cube is :
