Jee Main
Probability
JEE Main 2021 (Online) 1st September Evening Shift
INTEGER+4 / -12021
Let X be a random variable with distribution.
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If the mean of X is 2.3 and variance of X is \(\sigma\)2, then 100 \(\sigma\)2 is equal to :
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| x | \(-\)2 | \(-\)1 | 3 | 4 | 6 |
|---|---|---|---|---|---|
| P(X = x) | \({1 \over 5}\) | a | \({1 \over 3}\) | \({1 \over 5}\) | b |
If the mean of X is 2.3 and variance of X is \(\sigma\)2, then 100 \(\sigma\)2 is equal to :
