Jee Main
Differential Equations
JEE Main 2021 (Online) 26th August Evening Shift
MCQ+4 / -12021
Let y(x) be the solution of the differential equation
2x2 dy + (ey \(-\) 2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :
2x2 dy + (ey \(-\) 2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :
