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Redox Reactions

JEE Advanced / Chemistry / Physical Chemistry / 37 questions

ChemistryPhysical Chemistry37 PYQs

Practice 37 JEE Advanced Chemistry questions from Redox Reactions. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.

37
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Chemistry / Physical Chemistry
1980-2026
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2022-2026
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2017-2026

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37PYQs
MCQ35.1%
SUBJECTIVE35.1%
INTEGER16.2%
MCQM13.5%

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#1 Medium22
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Redox Reactions Questions

Showing 37 of 37 questions on this page.

1Redox Reactions
Reaction of PtF6 with oxygen (O2) gas results in the formation of an ionic compound, X+Y-.Correct statement(s) is(are)
MCQM+4 / -12026
2Redox Reactions
One of the products formed from the reaction of permanganate ion with iodide ion in neutral aqueous medium is
MCQ+3 / -12025
3Redox Reactions
Ozonolysis of ClO2 produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is __________.
INTEGER+4 / -02021
4Redox Reactions
A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ pre...
INTEGER+2 / -02021
5Redox Reactions
A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ pre...
INTEGER+2 / -02021
6Redox Reactions
Choose the correct statement(s) among the following :
MCQM+4 / -22020
7Redox Reactions
The order of the oxidation state of the phosphorous atom in
\({H_3}P{O_2},{H_3}P{O_4},{H_3}P{O_3}\) and \({H_4}{P_2}{O_6}\) is
MCQ+3 / -0.752017
8Redox Reactions
In neutral or faintly alkaline solution, 8 moles of permanganate anion quantitative oxidise thiosulphate anions to produce X moles of a sulphur containing product. The magnitude of X is....
INTEGER+3 / -02016
9Redox Reactions
Fe3+ is reduced to Fe2+ by using
MCQM+4 / -22015
10Redox Reactions
Consider the following list of reagents, acidified K2Cr2O7, alkaline KMnO4, CuSO4, H2O2, Cl2, O3, FeCl3, HNO3 and Na2S2O3. The total number of reagents that can oxidise aqueous iodide to iodine is
INTEGER+3 / -02014
11Redox Reactions
For the reaction,\({I^ - } + ClO_3^ - + {H_2}S{O_4} \to C{l^ - } + HSO_4^ - + {I_2}\)the correct statement(s) in the balanced equation is/are
MCQM+3 / -02014
12Redox Reactions
Reduction of the metal centre in aqueous permanganate ion involves
MCQM+4 / -22011
13Redox Reactions
The difference in the oxidation numbers of the two types of sulphur atoms in Na2S4O6 is
INTEGER+2 / -02011
14Redox Reactions
Match the reactions in Column I with nature of the reactions/type of the products in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 \(\times\) 4 matrix given in the ORS.

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MCQ+4 / -02007
15Redox Reactions
The reaction, \(3Cl{O^ - }(aq)\)\(\to ClO_3^ - (aq) + 2C{l^ - }(aq)\) is an example of :
MCQ+2 / -0.52001
16Redox Reactions
Amongst the following identify the species with an atom in +6 oxidation state
MCQ+2 / -0.52000
17Redox Reactions
The normality of 0.3 M phosphorus acid (H3PO3) is
MCQ+2 / -0.51999
18Redox Reactions
To a 25ml H2O2 solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20 ml of 0.3 N sodium thiosulphate solution. Calculate the volume strength of H2O2 solution.
SUBJECTIVE+5 / -01997
19Redox Reactions
A 5.0 cm3 solution of H2O2 liberates 0.508 g of iodine from an acidified KI solution. Calculate the strength of H2O2 solution in terms of volume strength at STP.
SUBJECTIVE+2 / -01995
20Redox Reactions
For the redox reaction:
\(MnO_4^ - + {C_2}O_4^{ - 2} + {H^ + }\) \(\to M{n^{2 + }} + C{O_2} + {H_2}O\)
The correct coefficients of the reactants for the balanced
reaction are
MCQ+1 / -0.251992
21Redox Reactions
The volume strength of 1.5 N H2O2 solution is
MCQ+1 / -0.251991
22Redox Reactions
The oxidation number of phosphorus in Ba(H2PO2) is :
MCQ+1 / -0.251990
23Redox Reactions
The equivalent weight of MnSO4 is half of its molecular weight, when it converts to
MCQ+1 / -0.251988
24Redox Reactions
Complete and balance the following equation:
S + OH- \(\to\) S2- + \(S_2O_3^-\)
SUBJECTIVE+1 / -01986
25Redox Reactions
Complete and balance the following equation:
\(ClO_3^-\) + I- + H2SO4 \(\to\) Cl- + \(HSO_4^-\)
SUBJECTIVE+1 / -01986
26Redox Reactions
Arrange the following in increasing oxidation number of iodine.
I2, HI, HIO4, ICl
SUBJECTIVE+1 / -01986
27Redox Reactions
Complete and balance the following equation:
Ag+ + AsH3 \(\to\) H3AsO3 + H+
SUBJECTIVE+1 / -01986
28Redox Reactions
Complete and balance the following equation:
Mn2+ + PbO2 \(\to\) \(MnO_4^-\) + H2O
SUBJECTIVE+1 / -01986
29Redox Reactions
Complete and balance the following equation:
HNO3 + HCl \(\to\) NO + Cl2
SUBJECTIVE+1 / -01983
30Redox Reactions
Complete and balance the following equation:
\(Cr_2O_7^{2-}\) + C2H4O \(\to\) C2H4O2 + Cr3+
SUBJECTIVE+1 / -01983
31Redox Reactions
Complete and balance the following equation:
Zn + \(NO_3^- \to\) Zn2+ + \(NH_4^+\)
SUBJECTIVE+1 / -01983
32Redox Reactions
Complete and balance the following equations:
Cl2 + OH- \(\to\) Cl- + ClO-
SUBJECTIVE+1 / -01983
33Redox Reactions
Complete and balance the following equation:
Ce3+ + \(S_2O_8^{-2} \to\) \(SO_4^{-2}\) + Ce4+
SUBJECTIVE+1 / -01983
34Redox Reactions
The oxidation number of carbon in CH2O is
MCQ+1 / -0.251982
35Redox Reactions
1 mole of N2H4 loses 10 moles of electrons to form a new compound Y. assuming that all nitrogen appears in the new compound , what is the oxidation state of nitrogen in Y ? (there is no change in the oxidation state of hydrogen)
MCQ+1 / -0.251981
36Redox Reactions
Balance the following Equations:
(i) Cu2O + H+ + \(NO_3^ - \to\) Cu2+ + NO + H2O
(ii) K4[Fe(CN)6] + H2SO4 + H2O \(\to\) K2SO4 + FeSO4 + (NH4)2SO4 + CO
(iii) C2H5OH + I2 + OH- \(\to\) CHI3 + \(HCO_3^-\) + I- + 4H2O
SUBJECTIVE+3 / -01981
37Redox Reactions
M is molecular weight of KMnO4. The equivalent wight of KMnO4 when it is converted into K2MnO4 is
MCQ+2 / -0.51980

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