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Rotational Motion

JEE Advanced 2026 Paper 1 Online

MCQ+3 / -12026

A solid cylinder of radius R rolls without slipping with a center of mass speed v0 = $\sqrt{\frac{gR}{3}}$ on a horizontal surface with a vertical edge, as shown in the figure. Here, g is the acceleration due to gravity. At the moment when the cylinder loses contact with the surface due to rotation around the corner, the speed of its center of mass is:


JEE Advanced 2026 Paper 1 Online Physics - Rotational Motion Question 4 English

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