Jee Advanced
Rotational Motion
JEE Advanced 2026 Paper 1 Online
MCQ+3 / -12026
A solid cylinder of radius R rolls without slipping with a center of mass speed v0 = $\sqrt{\frac{gR}{3}}$ on a horizontal surface with a vertical edge, as shown in the figure. Here, g is the acceleration due to gravity. At the moment when the cylinder loses contact with the surface due to rotation around the corner, the speed of its center of mass is:

