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Complex Numbers

JEE Advanced 2026 Paper 1 Online

INTEGER+4 / -02026

Let

\(\alpha = \left( 1 - 2\cos\left(\frac{\pi}{11}\right) \right) \left( 1 - 2\cos\left(\frac{3\pi}{11}\right) \right) \left( 1 - 2\cos\left(\frac{9\pi}{11}\right) \right) \left( 1 - 2\cos\left(\frac{27\pi}{11}\right) \right) \left( 1 - 2\cos\left(\frac{81\pi}{11}\right) \right).\)

Then the value of $5 - \alpha^2$ is ______________.

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