Jee Advanced
Complex Numbers
JEE Advanced 2026 Paper 1 Online
INTEGER+4 / -02026
Let
\(\alpha = \left( 1 - 2\cos\left(\frac{\pi}{11}\right) \right) \left( 1 - 2\cos\left(\frac{3\pi}{11}\right) \right) \left( 1 - 2\cos\left(\frac{9\pi}{11}\right) \right) \left( 1 - 2\cos\left(\frac{27\pi}{11}\right) \right) \left( 1 - 2\cos\left(\frac{81\pi}{11}\right) \right).\)
Then the value of $5 - \alpha^2$ is ______________.
