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Jee Advanced

Electrochemistry

JEE Advanced 2021 Paper 2 Online

MCQM+4 / -22021
Some standard electrode potentials at 298 K are given below :

Pb2+ /Pb = \(-\)0.13 V

Ni2+ /Ni = \(-\) 0.24 V

Cd2+ /Cd = \(-\) 0.40 V

Fe2+ /Fe = \(-\) 0.44 V

To a solution containing 0.001 M of X2+ and 0.1 M of Y2+, the metal rods X and Y are inserted (at 298 K) and connected by a conducting wire. This resulted in dissolution of X. The correct combination(s) of X and Y, respectively, is(are)

(Given : Gas constant, R = 8.314 J K\(-\) mol\(-\)1, Faraday constant, F = 96500 C mol\(-\)1)

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