Jee Advanced
Basics Of Organic Chemistry
JEE Advanced 2021 Paper 2 Online
MCQ+3 / -12021
The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s-character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below :

Cl \(-\) Cl (g) \(\to\) Cl\(_{(g)}^ \bullet\) + Cl\(_{(g)}^ \bullet\) \(\Delta\)H\(^\circ\) = 58 kcal mol\(-\)1
H3C \(-\) Cl (g) \(\to\) H3C\(_{(g)}^ \bullet\) + Cl\(_{(g)}^ \bullet\) \(\Delta\)H\(^\circ\) = 85 kcal mol\(-\)1
H \(-\) Cl (g) \(\to\) H\(_{(g)}^ \bullet\) + Cl\(_{(g)}^ \bullet\) \(\Delta\)H\(^\circ\) = 103 kcal mol\(-\)1

Cl \(-\) Cl (g) \(\to\) Cl\(_{(g)}^ \bullet\) + Cl\(_{(g)}^ \bullet\) \(\Delta\)H\(^\circ\) = 58 kcal mol\(-\)1
H3C \(-\) Cl (g) \(\to\) H3C\(_{(g)}^ \bullet\) + Cl\(_{(g)}^ \bullet\) \(\Delta\)H\(^\circ\) = 85 kcal mol\(-\)1
H \(-\) Cl (g) \(\to\) H\(_{(g)}^ \bullet\) + Cl\(_{(g)}^ \bullet\) \(\Delta\)H\(^\circ\) = 103 kcal mol\(-\)1
For the following reaction
CH4(g) + Cl2(g) \(\buildrel {light} \over \longrightarrow\) CH3Cl(g) + HCl (g)
the correct statement is
CH4(g) + Cl2(g) \(\buildrel {light} \over \longrightarrow\) CH3Cl(g) + HCl (g)
the correct statement is
