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Matrices And Determinants

IIT-JEE 2008 Paper 1 Offline

MCQ+3 / -12008

Consider the system of equations:


\(x-2y+3z=-1\)


\(-x+y-2z=k\)


\(x-3y+4z=1\)


Statement - 1 : The system of equations has no solution for \(k\ne3\).


and


Statement - 2 : The determinant \(\left| {\matrix{ 1 & 3 & { - 1} \cr { - 1} & { - 2} & k \cr 1 & 4 & 1 \cr } } \right| \ne 0\), for \(k \ne 3\).

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