Dual Nature Of Radiation

The potential energy of a particle of mass m
is given by

$$\mathrm{U}(x)=\left\{\begin{array}{cc}\mathrm{E}_{0} & 0 \leq x \leq 1 \\ 0 & x>1\end{array}\right.$$

\(\lambda_{1}\) and \(\lambda_{2}\) are the de Broglie wavelengths of the particle, when \(0 \leq x \leq 1\) and \(x > 1\), respectively. If the total energy of particle is \(2 \mathrm{E}_{0}\), find \(\frac{\lambda_{1}}{\lambda_{2}}\).