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Chemical Equilibrium PYQs - Last 10 Years

COMEDK / Chemistry / Physical Chemistry / 16 recent questions

ChemistryPhysical Chemistry2017-2026

Practice 16 COMEDK Chemistry questions from Chemical Equilibrium. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.

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Chemistry / Physical Chemistry
2020-2026
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12
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2022-2026
16
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2017-2026

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Last 10 Years Chemical Equilibrium Questions

Showing 16 of 16 filtered questions.

1Chemical Equilibrium
Consider the gaseous equilibrium
$2 \mathrm{AB}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{AB}_{(\mathrm{g})}+\mathrm{B}_{2(\mathrm{~g})}$
The expression relating the degree of dissociation ( $\alpha$ ) and equilibrium constant ( $K_p$ )...
MCQ+1 / -02026
2Chemical Equilibrium
If the equilibrium constant for $\mathrm{N}_{2(g)}+\mathrm{O}_{2(g)} \rightleftharpoons 2 \mathrm{NO}_{(g)}$ is 49 The equilibrium constant for the reaction $N O_{(g)} \rightleftharpoons \frac{1}{2} N_{2(g)}+\frac{1}{2} O_{2(g)}$ is $\_\_\_...
MCQ+1 / -02026
3Chemical Equilibrium
An equilibrium mixture taken in 2 litre vessel of the reaction: $2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})$ has 4 moles of $\mathrm{SO}_2, 3$ moles of $\mathrm{O}_2$ and 6 moles o...
MCQ+1 / -02026
4Chemical Equilibrium
Consider the reaction
\(\mathrm{Fe}_2 \mathrm{O}_3(\mathrm{~s})+3 \mathrm{CO}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{Fe}(\mathrm{l})+3 \mathrm{CQ}_2(\mathrm{~g})\)
In accordance with Le-Chatlier's principle, which of the following will n...
MCQ+1 / -02025
5Chemical Equilibrium
For a reaction,
\(A+B \rightleftharpoons 2 C\)
1.0 mole of $A, 1.5$ mole of $B$ and 0.5 mole of $C$ were taken in a 1 L vessel. At equilibrium, the concentration of $C$ was $1.0 \mathrm{~mol} \mathrm{~L}^{-1}$. The equilibrium constant for ...
MCQ+1 / -02025
6Chemical Equilibrium
For the reaction $\mathrm{P}+\mathrm{Q} \leq \mathrm{R}+\mathrm{S}$, carried out at 298 K , the equilibrium constant was found to be 169 and the initial concentrations of all reactants and products was 1.0 M . What is the equilibrium concen...
MCQ+1 / -02025
7Chemical Equilibrium
At \(700 \mathrm{~K}\), the Equilibrium constant value for the formation of \(\mathrm{HI}\) from \(\mathrm{H}_2\) and \(\mathrm{I}_2\) is 49.0 .
0.7 mole of \(\mathrm{HI}(\mathrm{g})\) is present at equilibrium. What will be the concentrati...
MCQ+1 / -02024
8Chemical Equilibrium
\(\mathrm{S}_8\) on heating at a temperature above \(1000 \mathrm{~K}\), changes to \(\mathrm{S}_2\). When 1 mole of \(\mathrm{S}_8\) is heated above \(1000 \mathrm{~K}\), the pressure falls by \(32 \%\) at equilibrium. The equilibrium cons...
MCQ+1 / -02024
9Chemical Equilibrium
The equilibrium constants for the reactions \(a, b\), and \(c\) are as given:
a) \(\mathrm{N}_2+3 \mathrm{H}_2=2 \mathrm{NH}_3: \mathbf{K}_1\)
b) \(\mathrm{N}_2+\mathrm{O}_2=2 \mathrm{NO}: \mathrm{K}_2\)
c) $$2 \mathrm{H}_2+\mathrm{O}_2=2 \...
MCQ+1 / -02023
10Chemical Equilibrium
Consider the following equilibrium,
$$\begin{aligned}
& 2 \mathrm{No}(g) \rightleftharpoons \mathrm{N}_2+\mathrm{O}_2 ; \mathrm{K}_{\mathrm{G}}=2.4 \times 10^{20} \\
& \mathrm{No}(\mathrm{g})+\frac{1}{2} \mathrm{Br}_2(\mathrm{~g}) \rightlef...
MCQ+1 / -02023
11Chemical Equilibrium
The equilibrium constant, \(K_C\) for \(3C_2H_2(g) \rightleftharpoons C_6H_6(g)\) is 4 L\(^2\)mol\(^{-2}\). If the equilibrium concentration of benzene is 0.5 mol\(^{-1}\) than what is the value of concentration of ethylene?
MCQ+1 / -02022
12Chemical Equilibrium
For the reaction, H\(_2\)(g) + I\(_2\)(g) \(\rightleftharpoons\) 2HI(g) the position of equilibrium can be shifted to the right by
MCQ+1 / -02022
13Chemical Equilibrium
In the chemical reaction,
N\(_2\) + 3H\(_2\) \(\rightleftharpoons\) 2NH\(_3\) at equilibrium point.
MCQ+1 / -02021
14Chemical Equilibrium
For the equilibrium,
2NOCl(g) \(\rightleftharpoons\) 2NO(g) + Cl\(_2\)(g),
the value of the equilibrium constant, \(K_C\) is 3.75 \(\times\) 10\(^{-6}\) at 1069 K. The value of \(K_p\) for the reaction at this temperature will be
MCQ+1 / -02021
15Chemical Equilibrium
In the equilibrium, \(AB\rightleftharpoons A+B\), if the equilibrium concentration of A is double, then equilibrium concentration of B will be
MCQ+1 / -02021
16Chemical Equilibrium
\(2S{O_2}(g) + {O_2}(g)\buildrel {{V_2}{O_5}} \over \rightleftharpoons\) is an example for
MCQ+1 / -02020