BitsatProbabilityBITSAT 2025MCQ+3 / -12025What is the probability of getting a sum of 9 in a single throw of three fair dice?A$\frac{6}{216}$B$\frac{36}{216}$C$\frac{9}{216}$D$\frac{25}{216}$Check AnswerClear SelectionReveal AnswerShow Explanation
