BitsatProbabilityBITSAT 2024MCQ+3 / -12024The probability of getting 10 in a single throw of three fair dice isA$ \frac{1}{6} $B$ \frac{1}{8} $C$ \frac{1}{9} $D$ \frac{1}{5} $Check AnswerClear SelectionReveal AnswerShow Explanation
