BitsatElectrostaticsBITSAT 2024MCQ+3 / -12024Electric field at point $ (30,30,0) $ due to a charge of $ 0.008 \mu \mathrm{C} $ placed at origin will be, (coordinates are in cm )A$ 8000 \mathrm{NC}^{-1} $B$ 4000(\hat{\mathbf{i}}+\hat{\mathbf{j}}) \mathrm{NC}^{-1} $C$ 200 \sqrt{2}(\hat{\mathbf{i}}+\hat{\mathbf{j}}) \mathrm{NC}^{-1} $D$ 400 \sqrt{2}(\hat{\mathbf{i}}+\hat{\mathbf{j}}) \mathrm{NC}^{-1} $Check AnswerClear SelectionReveal AnswerShow Explanation
