Bitsat
Sequences And Series
BITSAT 2023
MCQ+3 / -12023
Let \(\frac{1}{16}, a\) and \(b\) be in GP and \(\frac{1}{a}, \frac{1}{b}, 6\) be in AP, where \(a, b>0\). Then, \(72(a+b)\) is equal to
Bitsat
BITSAT 2023
Let \(\frac{1}{16}, a\) and \(b\) be in GP and \(\frac{1}{a}, \frac{1}{b}, 6\) be in AP, where \(a, b>0\). Then, \(72(a+b)\) is equal to