BitsatSequences And SeriesBITSAT 2024MCQ+3 / -12024If $ \sum\limits_{k=1}^{n} k(k+1)(k-1)=p n^{4}+q n^{3}+t n^{2}+s n $, where $ p, q, t $ and $ s $ are constants, then the value of $ s $ is equal toA$ -\frac{1}{4} $B$ -\frac{1}{2} $C$ \frac{1}{2} $D$ \frac{1}{4} $Check AnswerClear SelectionReveal AnswerShow Explanation
