BitsatDifferential EquationsBITSAT 2023MCQ+3 / -12023If \(\left(1+x^2\right) d y+2 x y d x=\cot x d x\), then the general solution beA\(y=\frac{\log |\sin x|}{1+x^2}+\frac{C}{1+x^2}\)B\(y=\frac{\log |\sin x|}{1-x^2}+\frac{C}{1-x^2}\)C\(y=\frac{\log |\cos x|}{1+x^2}+\frac{C}{1+x^2}\)D\(y=\frac{\log |\cos x|}{1-x^2}+\frac{C}{1-x^2}\)Check AnswerClear SelectionReveal AnswerShow Explanation
