BitsatDifferential EquationsBITSAT 2020MCQ+3 / -12020The solution of differential equation \((x{y^5} + 2y)dx - xdy = 0\), isA\(9{x^8} + 4{x^9}{y^4} = 9{y^4}C\)B\(9{x^8} - 4{x^9}{y^4} - 9{y^4}C = 0\)C\({x^8}(9 + 4{y^4}) = 10{y^4}C\)DNone of theseCheck AnswerClear SelectionReveal AnswerShow Explanation
