Bitsat
Limits Continuity And Differentiability
BITSAT 2021
MCQ+3 / -12021
If \(f(x) = \left\{ {\matrix{ {a{x^2} + 1,} & {x \le 1} \cr {{x^2} + ax + b,} & {x > 1} \cr } } \right.\) is differentiable at x = 1, then
Bitsat
BITSAT 2021
If \(f(x) = \left\{ {\matrix{ {a{x^2} + 1,} & {x \le 1} \cr {{x^2} + ax + b,} & {x > 1} \cr } } \right.\) is differentiable at x = 1, then