16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4e4,{"@context":"https://schema.org","@type":"Quiz","name":"Bitsat 2020 Ray Optics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/bitsat/questions/2020/physics/ray-optics/1l16uis68","educationalLevel":"Entrance exam preparation","about":"Bitsat / Physics / Ray Optics","hasPart":{"@type":"Question","name":"Bitsat 2020 Ray Optics PYQ with Solution","text":"A thin equi-convex lens is made of glass of refractive index 1.5 and its focal length is 0.2 m. If it acts as a concave lens of focal length 0.5 cm when dipped in a liquid, the refractive index of the liquid is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"The focal length of a convex lens of refractive index \\mu g in air, {1 \\over {{f_{air}}}} = ({\\mu _g} - 1)\\left( {{1 \\over {{R_1}}} - {1 \\over {{R_2}}}} \\right) ...... (i) where, R 1 , R 2 = radii of curvatures of its first and second surface. When the lens is immersed in a liquid of refractive index \\mu I , then refractive index of material of lens (glass) w.r.t. liquid is, {}_I{\\mu _g} = {{{\\mu _g}} \\over {{\\mu _I}}} ..... (ii) Now, focal length of lens in liquid {1 \\over {f'}} = ({}_I{\\mu _g..."}}}18:T592,

The focal length of a convex lens of refractive index $$\mu$$_g in air,

$${1 \over {{f_{air}}}} = ({\mu _g} - 1)\left( {{1 \over {{R_1}}} - {1 \over {{R_2}}}} \right)$$ ...... (i)

where, R₁, R₂ = radii of curvatures of its first and second

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