Ap Eapcet
Differentiation
AP EAPCET 2025 - 24th May Morning Shift
MCQ+1 / -02025
If $y=\tan ^{-1}\left(\frac{3 x-x^3}{1-3 x^2}\right)+\tan ^{-1}\left(\frac{7 x}{1-12 x^2}\right)$, then at $x=0, \frac{d y}{d x}=$
Ap Eapcet
AP EAPCET 2025 - 24th May Morning Shift
If $y=\tan ^{-1}\left(\frac{3 x-x^3}{1-3 x^2}\right)+\tan ^{-1}\left(\frac{7 x}{1-12 x^2}\right)$, then at $x=0, \frac{d y}{d x}=$