Ap EapcetDifferentiationAP EAPCET 2025 - 23rd May Evening ShiftMCQ+1 / -02025If $y=\tan ^{-1} \sqrt{x^2-1}+\sinh ^{-1} \sqrt{x^2-1}, x>1$, then $\frac{d y}{d x}=$A$\frac{1}{x \sqrt{x^2-1}}$B$\frac{x+1}{x \sqrt{x^2-1}}$C$\frac{x+1}{x^2 \sqrt{x^2-1}}$D$\frac{x}{\sqrt{x^2-1}}$Check AnswerClear SelectionReveal AnswerShow Explanation
