Ap EapcetIndefinite IntegrationAP EAPCET 2024 - 22th May Morning ShiftMCQ+1 / -02024\(\int \frac{1}{x^2\left(\sqrt{1+x^2}\right)} d x=\)A $\frac{-\sqrt{x^2+1}}{x}+c$B $\frac{\sqrt{x^2+1}}{x}+c$C $\frac{-\sqrt{x^2-1}}{x}+c$D $\frac{\sqrt{x^2-1}}{x}+c$Check AnswerClear SelectionReveal AnswerShow Explanation
