Ap EapcetIndefinite IntegrationAP EAPCET 2024 - 22th May Morning ShiftMCQ+1 / -02024\(\int \frac{x^3 \tan ^{-1} x^4}{1+x^8} d x=\)A $\frac{\left(\tan ^{-1}\left(x^4\right)\right)^2}{8}+c$B $\frac{\left(\left(\tan ^{-1}\left(x^4\right)\right)^3\right.}{3}+c$C $\frac{\left(\tan ^{-1}\left(x^4\right)\right)^2}{4}+c$ D$\frac{\left(\tan ^{-1}(x)^4\right)^2}{2}+c$Check AnswerClear SelectionReveal AnswerShow Explanation
