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AP EAPCET 2025 - 23rd May Evening Shift

AP EAPCET / 160 questions

2025Fri, May 23, 2025 9:30 AM160 PYQs
1Semiconductor Devices And Logic Gates
In common emitter amplifier of a transistor, if the ratio of the voltage gain and current amplification factor is 4 , then the ratio of the collector and base resistances is
MCQ+1 / -02025
2Semiconductor Devices And Logic Gates
If three logic gates are connected as shown in the figure, then the correct truth table of the circuit is
MCQ+1 / -02025
3Simple Harmonic Motion
The equations for the displacements of two particles in simple harmonic motion are $y_1=0.1 \sin \left(100 \pi t+\frac{\pi}{3}\right)$ and $y_2=0.1 \cos \pi t$ respectively. The phase difference between the velocities of the two particles a...
MCQ+1 / -02025
4Simple Harmonic Motion
A spring is stretched by 0.2 m when a mass of 0.5 kg is suspended to it. The time period of the spring when 0.5 kg mass is replaced with a mass of 0.25 kg is suspended to it is
(Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
MCQ+1 / -02025
5Units And Measurement And Dimensions
If the equation for the velocity of a particle at time ' $t$ ' is $v=$ at $+\frac{b}{t+c}$, then the dimensions of $a, b, c$ are respectively
MCQ+1 / -02025
6Vector Algebra
If $\alpha, \beta$ and $\gamma$ are the angles made by a vector with $x, y$ and $z$ axes respectively, then $\sin ^2 \alpha+\sin ^2 \beta=$
MCQ+1 / -02025
7Wave Optics
In Young's double slit experiment, if the distance between the slits is increased to 3 times initial distance, then the ratio of initial and final fringe widths is
MCQ+1 / -02025
8Waves
If two progressive sound waves represented by $y_1=3 \sin 250 \pi t$ and $y_2=2 \sin 260 \pi t$ (where displacement is in metre and time is in second) superimpose, then the time interval between two successive maximum intensities is
MCQ+1 / -02025
9Work Energy And Power
A circular well of diameter 2 m has water upto the ground level. If the bottom of the well is at a depth of 14 m , the time taken in seconds to empty the well using a 1.4 kW motor is
(Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
MCQ+1 / -02025
10Work Energy And Power
If a force of $\left(6 x^2-4 x\right) \mathrm{N}$ acts on a body of mass 10 kg , then work to be done by the force in displacing the body from $x=2 \mathrm{~m}$ to $x=4 \mathrm{~m}$ is
MCQ+1 / -02025

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