Chemical Kinetics
AIIMS / Chemistry / Physical Chemistry / 5 questions
ChemistryPhysical Chemistry5 PYQs
Practice 5 AIIMS Chemistry questions from Chemical Kinetics. Use the year-wise and type-wise breakdown to prioritize recent PYQs, then continue into the question list below.
5
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Chemistry / Physical Chemistry
2018-2019
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5
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2015-2019
5
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2010-2019
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2018
2019Latest year
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5PYQs
MCQ100%
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5 in last 5 years5 in last 10 years
Chemical Kinetics Questions
Showing 5 of 5 questions on this page.
1Chemical Kinetics
What is the activation energy \((\mathrm{kJ} / \mathrm{mol})\) for a reaction if its rate constant doubles when the temperature is raised from \(300 \mathrm{~K}\) to \(400 \mathrm{~K}\) of these $$(R=8.314 \mathrm{~Jmol}^{-1} \mathrm{~K}^{-...
MCQ+1 / -0.332019
2Chemical Kinetics
Find out time period of Ist order reaction. When reaction complete \(2 / 3 \mathrm{rd}\). If the value of rate constant is \(4.3 \times 10^{-4}\)
MCQ+1 / -0.332019
3Chemical Kinetics
Assertion (A) The reaction
$$\begin{aligned} 2 \mathrm{NO}+\mathrm{O}_2 & \longrightarrow 2 \mathrm{NO}_2 \\ \text { and } \quad 2 \mathrm{CO}+\mathrm{O}_2 & \longrightarrow 2 \mathrm{CO}_2 \end{aligned}$$
proceeds at the same rate because ...
$$\begin{aligned} 2 \mathrm{NO}+\mathrm{O}_2 & \longrightarrow 2 \mathrm{NO}_2 \\ \text { and } \quad 2 \mathrm{CO}+\mathrm{O}_2 & \longrightarrow 2 \mathrm{CO}_2 \end{aligned}$$
proceeds at the same rate because ...
MCQ+1 / -0.332018
4Chemical Kinetics
The rate constant for the first order
decomposition of a certain reaction is
described by the equation \(\ln k\left(\mathrm{~s}^{-1}\right)=14.34-\frac{1.25 \times 10^4 \mathrm{~K}}{T}\). The energy of activation for this reaction is
decomposition of a certain reaction is
described by the equation \(\ln k\left(\mathrm{~s}^{-1}\right)=14.34-\frac{1.25 \times 10^4 \mathrm{~K}}{T}\). The energy of activation for this reaction is
MCQ+1 / -0.332018
5Chemical Kinetics
Among the following statements, the correct statement about the half-life period for a first order reaction is
MCQ+1 / -0.332018
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