Given sequence of chemical equation is

$$\mathop {{C_4}{H_{10}}O}\limits_{(N)} \mathop {\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{{\text{H}_2}\text{S}{\text{O}_4}}^{{K_2}C{r_2}{O_7}}} }\limits_{(step\,I)} {C_4}{H_8}O\mathop {\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{\text{Warm}}^{{I_2}/\text{NaOH}}} }\limits_{(step\,II)} CH{I_3}$$

Here, N will be

WB JEE 2018 Chemistry - Alcohol and Ether Question 11 English Explanation 1

WB JEE 2018 Chemistry - Alcohol and Ether Question 11 English Explanation 1

(IUPAC name = Butan-2-ol)

Step I It involves the oxidation of secondary alcohol to corresponding alcohol in the presence of K₂Cr₂O₇ and H₂SO₄.

WB JEE 2018 Chemistry - Alcohol and Ether Question 11 English Explanation 2

WB JEE 2018 Chemistry - Alcohol and Ether Question 11 English Explanation 2

Step II It involves the iodoform reaction. Ketone formed in step I have one methyl group linked to the carbonyl atom are oxidised by sodium hypohalite to sodium salts of corresponding carboxylic acids having one carbon atom less than that of carbonyl compound.

WB JEE 2018 Chemistry - Alcohol and Ether Question 11 English Explanation 3

WB JEE 2018 Chemistry - Alcohol and Ether Question 11 English Explanation 3

Alcohol And Ether

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