Wb JeeCircleWB JEE 2008MCQ+1 / -0.252008The locus of the centres of the circles which touch both the axes is given byA\({x^2} - {y^2} = 0\)B\({x^2} + {y^2} = 0\)C\({x^2} - {y^2} = 1\)D\({x^2} + {y^2} = 1\)Check AnswerClear SelectionReveal AnswerShow Explanation
