16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T519,{"@context":"https://schema.org","@type":"Quiz","name":"Viteee 2024 Fluid Mechanics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/viteee/questions/2024/physics/fluid-mechanics/m9bd5es0","educationalLevel":"Entrance exam preparation","about":"Viteee / Physics / Fluid Mechanics","hasPart":{"@type":"Question","name":"Viteee 2024 Fluid Mechanics PYQ with Solution","text":"In a car lift, compressed air exerts a force F_1 on a small piston having a radius of 5.0 cm . This pressure is transmitted to a second piston of radius 15.0 cm . If the mass of the car to be lifted is 1350 kg . The force on a small piston is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"Let the radii of the pistons be: Small piston: r_1 = 5.0 \\, \\text{cm} = 0.05 \\, \\text{m} Large piston: r_2 = 15.0 \\, \\text{cm} = 0.15 \\, \\text{m} The car of mass m = 1350 \\, \\text{kg} is lifted by the large piston. So, the weight of the car (the downward force) is: F_2 = mg = 1350 \\times 9.8 = 13230 \\, \\text{N} According to Pascal's law , the pressure is the same on both pistons: \\frac{F_1}{A_1} = \\frac{F_2}{A_2} where A_1 and A_2 are the areas of the pistons. Since area A = \\pi r^2 , we can wr..."}}}18:T46b,

Let the radii of the pistons be:

Small piston: $ r_1 = 5.0 \, \text{cm} = 0.05 \, \text{m} $
Large piston: $ r_2 = 15.0 \, \text{cm} = 0.15 \, \text{m} $

The car of mass $ m = 13

Fluid Mechanics

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