16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T522,{"@context":"https://schema.org","@type":"Quiz","name":"Viteee 2024 Electrostatics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/viteee/questions/2024/physics/electrostatics/m9bd48ia","educationalLevel":"Entrance exam preparation","about":"Viteee / Physics / Electrostatics","hasPart":{"@type":"Question","name":"Viteee 2024 Electrostatics PYQ with Solution","text":"Two point charges of +3 \\mu \\mathrm{C} and -3 \\mu \\mathrm{C} are placed at a certain distance apart from each other. Electric potential at a distance 60 cm from the mid-point of dipole on axial line is 150 V , then the value of dipole length is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"Given: Electric potential, V = 150 \\, \\text{V} Distance from the mid-point of the dipole on the axial line, r = 60 \\, \\text{cm} = 0.6 \\, \\text{m} The formula for the electric potential V on the axial line is: V = \\frac{1}{4 \\pi \\varepsilon_0} \\cdot \\frac{p \\cos \\theta}{r^2} For the axial line, \\theta = 0^\\circ . Thus, the potential becomes: V = \\frac{1}{4 \\pi \\varepsilon_0} \\cdot \\frac{p \\cdot 1}{r^2} Substitute the given values: 150 = \\frac{9 \\times 10^9 \\times p}{(0.6)^2} Solving for p : p =..."}}}18:T463,

Given:

Electric potential, $ V = 150 \, \text{V} $

Distance from the mid-point of the dipole on the axial line, $ r = 60 \, \text{cm} = 0.6 \, \text{m} $

The formula for the electric pot

Electrostatics

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