ViteeeLogarithmsVITEEE 2024MCQ+4 / -12024$\log \left(\log _{a b} a+\frac{1}{\log _b a b}\right)$ is $($ where $a b \neq 1)$A0B1C$\log _a a b$D$\log _b a b$Check AnswerClear SelectionReveal AnswerShow Explanation
