Motion

The position of a projectile launched from the origin at \(t=0\) is given \(\mathbf{r}=(40 \hat{\mathbf{i}}+50 \hat{\mathbf{j}}) \mathrm{m}\) at \(t=2 \mathrm{~s}\). If the projectile was launded at an angle \(\theta\) from the horizontal, then \(\theta\) is (take, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )