Viteee
Binomial Theorem
VITEEE 2023
MCQ+4 / -12023
If \(x^n=a_0+a_1(1+x)+a_2(1+x)^2+\ldots \ldots \ldots+ a_n(1+x)^n=b_0+b_1(1-x)+b_2(1-x)^2+\ldots . .+ b_n(1-x)^n\), then for \(n=201,\left(a_{101}, b_{101}\right)\) is equal to
Viteee
VITEEE 2023
If \(x^n=a_0+a_1(1+x)+a_2(1+x)^2+\ldots \ldots \ldots+ a_n(1+x)^n=b_0+b_1(1-x)+b_2(1-x)^2+\ldots . .+ b_n(1-x)^n\), then for \(n=201,\left(a_{101}, b_{101}\right)\) is equal to