ViteeeIndefinite IntegrationVITEEE 2022MCQ+4 / -12022The integral \(\int \frac{d x}{x^2\left(x^4+1\right)^{3 / 4}}\) equalsA\(\left[\frac{x^4+1}{x^4}\right]^{1 / 4}+C\)B\(\left(x^4+1\right)^{1 / 4}+C\)C\(-\left(x^4+1\right)^{1 / 4}+C\)D\(-\left(\frac{x^4+1}{x^4}\right)^{1 / 4}+C\)Check AnswerClear SelectionReveal AnswerShow Explanation
