ViteeeDifferential EquationsVITEEE 2022MCQ+4 / -12022The solution of \(\frac{d y}{d x}=1+x+y+x y\) isA\(\log (1+y)=x+\frac{x^2}{2}+C\)B\(x+y=C(1+x y)\)C\(\log (1+x)+x+y=C\)DNone of the aboveCheck AnswerClear SelectionReveal AnswerShow Explanation
