Viteee
Limits Continuity And Differentiability
VITEEE 2021
MCQ+4 / -12021
If $$f(x)=\left\{\begin{array}{cc}\frac{(1-\cos 4 x)}{x^2}, & \text { if } x < 0 \\ a, & \text { if } x=0, \\ \frac{\sqrt{x}}{\sqrt{(16+\sqrt{x})}-4}, & \text { if } x > 0\end{array}\right.$$ then \(f(x)\) is continuous at \(x=0\), for \(a\)
