Viteee
Differentiation
VITEEE 2021
MCQ+4 / -12021
If \(y=1+\frac{x}{1 !}+\frac{x^2}{2 !}+\frac{x^3}{3 !} \ldots\), then \(\frac{d y}{d x}\) is equal to
Viteee
VITEEE 2021
If \(y=1+\frac{x}{1 !}+\frac{x^2}{2 !}+\frac{x^3}{3 !} \ldots\), then \(\frac{d y}{d x}\) is equal to