Electrochemistry

An electrochemical cell has two half cell reactions as,

$$\begin{aligned} A^{2+}+2 e^{-} & \longrightarrow A ; E_{A^{2+} / A}^0=0.34 \mathrm{~V} \\ X & \longrightarrow X^{2+}+2 e^{-} ; E_{X^{2+} / X}^0=-2.37 \mathrm{~V} \end{aligned}$$

The cell voltage will be