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Simple Harmonic Motion

TG EAPCET 2025 (Online) 4th May Evening Shift

MCQ+1 / -02025

The force ( $F$ in newton) acting on a particle of mass 90 g executing simple harmonic motion is given by $F+0.04 \pi^2 y=0$, where $y$ is displacement of the particle in metre. If the amplitude of the particle is $\frac{6}{\pi} \mathrm{~m}$, then the maximum velocity of the particle is


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