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Motion In A Plane

TG EAPCET 2025 (Online) 4th May Evening Shift

MCQ+1 / -02025

The vertical displacement ( $y$ in metre) of a projectile in term of its horizontal displacement ( $x$ in metre) is given by $y=\left(\sqrt{3} x-0.2 x^2\right)$. The time of flight of the projectile is


(Acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )


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