Ts Eamcet
Indefinite Integration
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ+1 / -02025
If $\int \frac{d x}{\left(x^2+9\right) \sqrt{x^2+16}}=\frac{1}{3 \sqrt{7}} \tan ^{-1}\left(K \frac{x}{\sqrt{16+x^2}}\right)+c$, then $K=$
Ts Eamcet
TG EAPCET 2025 (Online) 2nd May Evening Shift
If $\int \frac{d x}{\left(x^2+9\right) \sqrt{x^2+16}}=\frac{1}{3 \sqrt{7}} \tan ^{-1}\left(K \frac{x}{\sqrt{16+x^2}}\right)+c$, then $K=$