Ts Eamcet
Differentiation
TG EAPCET 2025 (Online) 2nd May Morning Shift
MCQ+1 / -02025
If $\left(x^2-3 x+2\right)^{\frac{y}{x^{2-1}}}=x+2$, then $\left(\frac{d y}{d x}\right)_{x=0}=$
Ts Eamcet
TG EAPCET 2025 (Online) 2nd May Morning Shift
If $\left(x^2-3 x+2\right)^{\frac{y}{x^{2-1}}}=x+2$, then $\left(\frac{d y}{d x}\right)_{x=0}=$