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Definite Integration

TG EAPCET 2025 (Online) 2nd May Evening Shift

MCQ+1 / -02025

\(\mathop {\lim }\limits_{n \to \infty } \frac{1}{n^2}\left[e^{1 / n}+2 e^{2 / n}+3 e^{3 / n}+\ldots+2 n e^2\right]=\)

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