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TG EAPCET 2025 (Online) 4th May Evening Shift

MCQ+1 / -02025

If $Z=r(\cos \theta+i \sin \theta),\left(\theta \neq-\frac{\pi}{2}\right)$ is solution of $x^3=i$, then $r^9(\cos \theta+i \sin \theta)^9=x^{3-}=i$


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